A solution of malonic acid, H2C3H2O4, was standardized by titration with 0.100M NaOH solution. IF 21.82 mL of NaOH solutions were required to neutralize completely 12.12mL of the malonic acid solution, what is the molarity of the malonic acid solution?
moles OH- = 21.82 x 0.100 / 1000 = 0.00218
Malonic acid has 2 H+ so moles of malonic acid = 0.00218/2 = 0.00109
12.12 mL = 0.01212 L
0.00109 / 0.01212 = 0.0899 M
February 26th, 2010 at 6:51 am
moles OH- = 21.82 x 0.100 / 1000 = 0.00218
Malonic acid has 2 H+ so moles of malonic acid = 0.00218/2 = 0.00109
12.12 mL = 0.01212 L
0.00109 / 0.01212 = 0.0899 M
References :